Unit of concentration of solution:
Molarity (M): Molarity of a solution is the number of moles of solute dissolved per litre of solution. Thus,
Molarity (M) = Number of moles of solute/Volume of solution in litres
If WA gram of solute is present in V ml of a given solution, then-
Molarity (M) = (WA/Molar mass x1000/V)
Molality (m): Molality is the number of moles of the solute dissolved per l000g (or 1 kg) of the solvent. It is denoted by m. Therefore,
Molality (m) =Number of moles of solute/Mass of solvent in 1 kg or l000g
If WA gram of solute is present in WB gram of solvent, then
Molality (m) = (WA/Molar mass x1000/WB)
Mole Fraction (X):
Mole fraction is the ratio of number of moles of solute or solvent to the total number of moles present in the solution. It is denoted by X. Let us consider nA and nB be the number of moles of A and B present in solution. Then,
Mole fraction of solute A, XA = nA / (nA + nB) ————– (1)
Mole fraction of solute B, XB = nB / (nA + nB) ————– (2)
Adding expression (1) & (2), we have
XA + XB = nA / (nA + nB ) + nB / (nA + nB) =1
Therefore, sum of mole fractions of all the components in solution is always equal to one.
Normality (N): Normality of a solution is the number of gram equivalent of solute dissolved per litre of the given solution. Therefore,
Normality (N) =Number of gram equivalent of solute/Volume of solution in litres
If WA gram of solute is present in V ml of a given solution, then
Molality (m) = WA /Eq. mass x 1000/V
Percentage (%): The mass percentage of a component in a given solution is the mass of the component per 100g of the Solution. The % may be express in the following ways:
- (w/w) %
- (w/v) %
- (v/w) %
- (v/v) %
Raoult’s Law for solution containing non-volatile solute:
According to Raoult’s law, at a given temperature, the vapour pressure of a solution containing non-volatile solute is directly proportional to the mole fraction of the solvent. If PA is the vapour pressure of a solution containing non-volatile solute and XB is its mole fraction. Then,
PA α XB
Or, PA = K XB Where, K = Proportionality constant.
For pure solvent, XB = 1, then K becomes equal to vapour pressure of pure solvent which is denoted by P°A Therefore,
PA = PA° XB (PA = PA°)